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I have the points $O, A, B$ and $C$.
Relative to $O$, the position vectors of $A$, $B$ and $C$ are $(1,4, 2 )$, $ (3, 3, 3) $, $( 2, -1, 1)$
Want to show that the lines $OB$ and $AC$ bisect each other.
Is it sufficient to show that $\frac{1}{2} \vec{OB} = \vec{OA} + \frac{1}{2} \vec{AC}$?
Are there other ways using vectors?
1 Answer
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Yes, your method is correct.
You may also show that $$ \vec{OA} = \vec{CB} $$ and $$ \vec{OC} = \vec{AB} $$ which make the quadrilateral OABC into a parallelogram where the diagonals bisect each other.
