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How can I solve an exponent in a equation using base 10 logarithm tables? For an example, $$a = b^x$$ can be written as $$ \log_{10} a= x\log_{10}b $$ $$ x = \frac{ \log_{10}b }{\log_{10}a} $$ After this point I can refer values for $\log a$ and $\log b$ from the table. From this point how can I solve to get $x$. Can I subtract values since log division is subtraction??? Or should I take antilog. I'm Kinda stuck here Can Anyone help?
1 Answer
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It seems like you're pretty much done. For example, let's say you've found $\log_{10}b = 6$ and $\log_{10}a = 2$. Then $x = \frac{6}{2} = 3$.
