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Here is my linear equation:
Solve for p:
$\frac{5}{6} = \frac{n}{72} = \frac{m+n}{84} = \frac{p-m}{120}$
How am I supposed to solve for this 1 variable when there are multiple equal signs and 3 variables.
1 Answer
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Here's a hint: approach it in steps.
- You can use the equation $\frac{5}{6}=\frac{n}{72}$ to solve for $n$.
- You can use the equation $\frac{n}{72}=\frac{m+n}{84}$ to solve for $m$.
Can you see where this is going?
