How to Solve This Derivative Question?

How to Solve This Derivative Question?
$\begingroup$

I am in a bit over my head with a math course I joined voluntarily. This is the first question. I am learning but not as fast as it seems.

Q: If $f:(-{\displaystyle \pi }/6,{\displaystyle \pi }/6) \rightarrow \Bbb R$ is defined by $f(x)=2^x\tan(3x)$ for every $x {\displaystyle \in } (-{\displaystyle \pi }/6,{\displaystyle \pi }/6)$, then $f'(0)$ will be equal to (a) $\ln 2$ (b) $0$ (c) $2{\displaystyle \pi }$ (d) $3$

I want to know how to solve this, and what the chapter this is from and whats the exact resource that can help me learn this. I have figured this is linear approximation. Is that right ?

(And Boy, I just learned Latex, that was so much fun :)

$\endgroup$
2

1 Answer

$\begingroup$

It's just rules of derivatives, like product and chain;

evaluate $f'(x)=\ln2\cdot2^x\tan(3x)+2^x\sec^2(3x)\cdot3$ at $x=0$.

$\endgroup$
12

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Chloe Bennett
Author

Chloe Bennett

Chloe Bennett explores the intersection of pop culture, streaming entertainment, digital trends, and contemporary lifestyle. Her weekly commentary reaches thousands of culture enthusiasts.