Spectral Radius and Dominant Eigenvalue

Spectral Radius and Dominant Eigenvalue
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What is the difference between the spectral radius and dominant eigenvalue? If they are one and the same then why do both get mentioned, for instance here

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1 Answer

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Let $A$ be a matrix, and $\sigma(A)$ signifies the set of all eigenvalues$(\lambda_i)$ of $A$. Then

An eigenvalue of $A$ that is larger in absolute value than any other eigenvalue is called the dominant eigenvalue.

But

Spectral radius of $A$, which is denoted by $\rho(A)$ is defined as: $\rho(A) = \max\{|\lambda|:\lambda\ \epsilon\hspace{1mm}\sigma(A)$

Thus, spectral radius is more widely applicable; every matrix has a well defined spectral radius. Not every matrix has a dominant eigenvalue but there are theorems guaranteeing the existence of a dominant eigenvalue under appropriate conditions; first among these is the Perron-Frobenius theorem.

Matrices with dominant eigenvalues often arise in numerical approximation schemes for differential equations and the "stiffness" of a system can be quantified in terms of the size of the dominant eigenvalue. Rather than compute the exact value of the dominant eigenvalue, a numerical scheme might use a cheaper estimate of the spectral radius to determine stiffness. This is why both terms are mentioned in your link.

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