Equivalence Relation and Sets

Equivalence Relation and Sets
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The question:

Let $X$ and $Y$ be two sets, and let $S$ be an equivalence relation on set $X$ and $T$ be an equivalence relation on set $Y$. Define a relation $R$ on $X ×Y$ by $(a,b)R(c,d)$ if and only if $aSc$ and $bTd$.

Prove that $R$ is an equivalence relation on $X × Y$

The confusion:

I understand that I need to show that: reflexive, symmetric, and transitive properties hold in order for this to be an equivalence relation, but I don't understand what is in the two sets which from what I gather is the hard point of the problem. Then again even if I did know what was in each set, likely I still would need help showing the 3 properties hold. Then again this is my first problem of this sort so... Anyhow, would $X$={a,b} and $Y$={c,d}? That's about as far as I can go which likely is also wrong. Any help greatly appreciated. Thanks.

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1 Answer

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Reflexive: Take $(x,y)\in X \times Y$, since S and T are reflexive $xSx$ and $yTy$, therefore $(x,y)R(x,y)$.

Transitive: Let $(x_1,y_1)R(x_2,y_2)$ and $(x_2,y_2)R(x_3,y_3)$. Then by definition of R we have $x_1 S x_2$, $x_2 S x_3$, $y_1 T y_2$ and $y_2 T y_3$. But since S and T are transitive we have $x_1 S x_3$ and $y_1 T y_3$. Therefore $(x_1,y_1)R(x_3,y_3)$, hence R is transitive.

Symmetric: Let $(x_1,y_1)R(x_2,y_2)$, then by definition of R we have $x_1 S x_2$, $y_1 T y_2$. Since S and T are symmetric we have $x_2 S x_1$, and $y_2 T y_1$. Therefore we have $(x_2,y_2)R(x_1,y_1)$, hence it is symmetric.

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David Miller
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David Miller

David Miller brings 15 years of experience in global economics, personal finance strategy, and market dynamics. He specializes in turning complex economic trends into actionable insights for everyday readers.