Distribution and Absolute Value

Distribution and Absolute Value
$\begingroup$

I have a question about distribution and absolute values. I was solving a problem and was wondering if it would be okay to distribute a number into an absolute value with two terms. For example $3|2x+3|+3x^2-5$, is it okay to distribute the $3$ into $|2x+3|$ to get $|6x+9|$? I have searched this on Google but people said it was not okay to do it, but someone else said it was okay to do it. I am really confused, could someone clear this up for me?

$\endgroup$

2 Answers

$\begingroup$

If the multiplier is non-negative, it's OK. For example, $2|x| = |2x|$ but $-3|x|=-|3x|$.

$\endgroup$
$\begingroup$

There is a definite fact to use here, namely that $|a\cdot b| = |a|\cdot|b|$ for any two real numbers. Since $3>0$, we have:

$3\cdot|2x+3| = |3|\cdot|(2x+3)| = |(3)\cdot(2x+3)|$

Distributing the $3$ gives us $|6x+9|$.

$\endgroup$
0

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

James H. Sterling
Author

James H. Sterling

James Sterling reports on renewable energy developments, climate policy, ecological conservation, and green tech innovations around the globe.