Could someone explain why you multiply the lengths and add the angles when multiplying polar coordinates?
I tried multiplying the polar forms ($r_1\left(\cos\theta_1 + i\sin\theta_1\right)\cdot r_2\left(\cos\theta_2 + i\sin\theta_2\right)$), and expanding/factoring the result, and end up multiplying the lengths but can't seem to come to an equation where you add the angles.
2 Answers
By multiplying things out as usual, you get
$$[r_1(\cos\theta_1 + i\sin\theta_1)][r_2(\cos\theta_2 + i\sin\theta_2)] = r_1r_2(\cos\theta_1\cos\theta_2 - \sin\theta_1\sin\theta_2 + i[\sin\theta_1\cos\theta_2 + \sin\theta_2\cos\theta_1]).$$
Now you want to use the trig identities $\cos\theta_1\cos\theta_2 - \sin\theta_1\sin\theta_2 = \cos(\theta_1 + \theta_2)$ and $\sin\theta_1\cos\theta_2 + \sin\theta_2\cos\theta_1 = \sin(\theta_1 + \theta_2)$ to conclude that this is in fact $$r_1r_2[\cos(\theta_1 + \theta_2) + i\sin(\theta_1 + \theta_2)].$$
It might be useful to write the numbers as
$$z_1= \nu e^{i\theta}$$
$$z_2= \mu e^{i\psi}$$
Then one has
$$z_1\cdot z_2 =\nu \mu \cdot e^{(\psi+\theta)i}$$
This representation stems from Euler's formula
$$e^{i \theta}=\cos \theta+i\sin \theta$$
which I suspect you haven't been told about yet.
