Jordan Lemma Not Applying

Jordan Lemma Not Applying
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so I was trying to evaluate the integral of

{1/(x-ia) dx}

from -infinity to +infinity and where a>0

Of course, Jordan's lemma doesn't apply (it's what I used before, this is the case where the exponential equals to 1)

I'm really stuck...I've tried to use Cauchy's theorem but it just gives me zero and I'm quite sure it's not correct...

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1 Answer

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Hint: $ 1/(x - ai) + 1/(-x - ai) = 2ai/(x^2 + a^2) $, so what happens if you integrate $ 1/(x- ai) $ from $ x = -L $ to $ x = L $ for some finite $ L $?

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David Miller
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David Miller

David Miller brings 15 years of experience in global economics, personal finance strategy, and market dynamics. He specializes in turning complex economic trends into actionable insights for everyday readers.