$\begingroup$
$\endgroup$
3
Since the last angle is $77^\circ,$ can I solve this by using law of sines? This would lead us to:
$$\frac{519}{\sin\left(77^\circ\right)}=\frac{190+x}{\sin \left( 60^\circ \right)}$$
And the answer would be $\sim271,29$ meters
1 Answer
$\begingroup$
$\endgroup$
1
Make $x$ the subject of your equation. $$x+190=519\times\frac{\sin{60^\circ}}{\sin{77^\circ}}$$ $$x=519\times\frac{\sin{60^\circ}}{\sin{77^\circ}}-190\approx 271.29$$
