I am having problems converting this formula V = 4/3 π r^3. I used Math.PI and Math.pow, but I get this error:
';' expected
Also, the diameter variable doesn't work. Is there an error there?
import java.util.Scanner;
import javax.swing.JOptionPane;
public class NumericTypes
{
public static void main (String [] args)
{
double radius;
double volume;
double diameter;
diameter = JOptionPane.showInputDialog("enter the diameter of a sphere.");
radius = diameter / 2;
volume = (4 / 3) Math.PI * Math.pow(radius, 3);
JOptionPane.showMessageDialog("The radius for the sphere is "+ radius
+ "and the volume of the sphere is ");
}
}
4 Answers
You're missing the multiplication operator. Also, you want to do 4/3 in floating point, not integer math.
volume = (4.0 / 3) * Math.PI * Math.pow(radius, 3);
^^ ^
Here is usage of Math.PI to find circumference of circle and Area
First we take Radius as a string in Message Box and convert it into integer
public class circle {
public static void main(String[] args) {
// TODO code application logic here
String rad;
float radius,area,circum;
rad = JOptionPane.showInputDialog("Enter the Radius of circle:");
radius = Integer.parseInt(rad);
area = (float) (Math.PI*radius*radius);
circum = (float) (2*Math.PI*radius);
JOptionPane.showMessageDialog(null, "Area: " + area,"AREA",JOptionPane.INFORMATION_MESSAGE);
JOptionPane.showMessageDialog(null, "circumference: " + circum, "Circumfernce",JOptionPane.INFORMATION_MESSAGE);
}
}
Replace
volume = (4 / 3) Math.PI * Math.pow(radius, 3);
With:
volume = (4 * Math.PI * Math.pow(radius, 3)) / 3;
Your diameter variable won't work because you're trying to store a String into a variable that will only accept a double. In order for it to work you will need to parse it
Ex:
diameter = Double.parseDouble(JOptionPane.showInputDialog("enter the diameter of a sphere.");
