Here's my code:
import math
print("Hey, lets solve Task 4 :)")
number1 = input("How many digits do you want to look at? ")
number2 = input("What would you like the digits to add up to? ")
if number1 == 1:
cow = range(0,10)
elif number1 == 2:
cow = range(10,100)
elif number1 == 3:
cow = range(100,1000)
elif number1 == 4:
cow = range(1000,10000)
elif number1 == 5:
cow = range(10000,100000)
elif number1 == 6:
cow = range(100000,1000000)
elif number1 == 7:
cow = range(1000000,10000000)
elif number1 == 8:
cow = range(10000000,100000000)
elif number1 == 9:
cow = range(100000000,1000000000)
elif number1 == 10:
cow = range(1000000000,10000000000)
number3 = cow[-1] + 1
n = 0
while n < number3:
number4 = list(cow[n])
n += 1
I am looking to make a loop so that for each element in the list, it will get broken down into each of it's characters. For example, say the number 137 was in the list then it would be turned into [1,3,7]. Then I want to add these numbers together (I haven't started that bit yet but I have some idea of how to do it).
However, I keep getting this error message:
TypeError: 'int' object is not iterable
What am I doing wrong?
4 Answers
Your problem is with this line:
number4 = list(cow[n])
It tries to take cow[n], which returns an integer, and make it a list. This doesn't work, as demonstrated below:
>>> a = 1
>>> list(a)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: 'int' object is not iterable
>>>
Perhaps you meant to put cow[n] inside a list:
number4 = [cow[n]]
See a demonstration below:
>>> a = 1
>>> [a]
[1]
>>>
Also, I wanted to address two things:
- Your while-statement is missing a
:at the end. - It is considered very dangerous to use
inputlike that, since it evaluates its input as real Python code. It would be better here to useraw_inputand then convert the input to an integer withint.
To split up the digits and then add them like you want, I would first make the number a string. Then, since strings are iterable, you can use sum:
>>> a = 137
>>> a = str(a)
>>> # This way is more common and preferred
>>> sum(int(x) for x in a)
11
>>> # But this also works
>>> sum(map(int, a))
11
>>>
If the case is:
n=int(input())
Instead of -> for i in n: -> gives error- int object is not iterable
Use -> for i in range(0,n):works fine..!
This is very simple you are trying to convert an integer to a list object !!! of course it will fail and it should ...
To demonstrate/prove this to you by using the example you provided ...just use type function for each case as below and the results will speak for itself !
>>> type(cow)
<class 'range'>
>>>
>>> type(cow[0])
<class 'int'>
>>>
>>> type(0)
<class 'int'>
>>>
>>> >>> list(0)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: 'int' object is not iterable
>>>
def hourglassSum(arr):
sum1 = []
# Write your code here
for i in range(0,len(arr)-2):
for j in range(0,len(arr)-2):
x = sum(arr[i][j]+arr[i+1][j+1]+arr[i+2][j]+arr[i][j+1]+arr[i][j+2]+arr[i+2][j+1]+arr[i+2][j+2])
sum1.append(x)
#sum1.append(arr[i][j]+arr[i][j+1]+arr[i][j+2]+arr[i+1][j+1]+arr[i+2][j]+arr[i+2][j+1]+arr[i+2][j+2])
return max(sum1)
# Why x = sum(arr[i][j]+arr[i+1][j+1]+arr[i+2][j]+arr[i][j+1]+arr[i][j+2]+arr[i+2][j+1]+arr[i+2][j+2]) is showing TypeError: 'int' object is not iterable
and if we run the comment statement below the statement than it runs properly..
