I have a regular expression like this:
regexp = u'ba[r|z|d]'
Function must return True if word contains bar, baz or bad. In short, I need regexp analog for Python's
'any-string' in 'text'
How can I realize it? Thanks!
5 Answers
import re
word = 'fubar'
regexp = re.compile(r'ba[rzd]')
if regexp.search(word):
print('matched')
The best one by far is
bool(re.search('ba[rzd]', 'foobarrrr'))
Returns True
Match objects are always true, and None is returned if there is no match. Just test for trueness.
Code:
>>> st = 'bar'
>>> m = re.match(r"ba[r|z|d]",st)
>>> if m:
... m.group(0)
...
'bar'
Output = bar
If you want search functionality
>>> st = "bar"
>>> m = re.search(r"ba[r|z|d]",st)
>>> if m is not None:
... m.group(0)
...
'bar'
and if regexp not found than
>>> st = "hello"
>>> m = re.search(r"ba[r|z|d]",st)
>>> if m:
... m.group(0)
... else:
... print "no match"
...
no match
As @bukzor mentioned if st = foo bar than match will not work. So, its more appropriate to use re.search.
Here's a function that does what you want:
import re
def is_match(regex, text):
pattern = re.compile(regex)
return pattern.search(text) is not None
The regular expression search method returns an object on success and None if the pattern is not found in the string. With that in mind, we return True as long as the search gives us something back.
Examples:
>>> is_match('ba[rzd]', 'foobar')
True
>>> is_match('ba[zrd]', 'foobaz')
True
>>> is_match('ba[zrd]', 'foobad')
True
>>> is_match('ba[zrd]', 'foobam')
False
You can do something like this:
Using search will return a SRE_match object, if it matches your search string.
>>> import re
>>> m = re.search(u'ba[r|z|d]', 'bar')
>>> m
<_sre.SRE_Match object at 0x02027288>
>>> m.group()
'bar'
>>> n = re.search(u'ba[r|z|d]', 'bas')
>>> n.group()
If not, it will return None
Traceback (most recent call last):
File "<pyshell#17>", line 1, in <module>
n.group()
AttributeError: 'NoneType' object has no attribute 'group'
And just to print it to demonstrate again:
>>> print n
None
