You could use the PHP in_array function

if( in_array( "bla" ,$yourarray ) )
{
    echo "has bla";
}

Using: in_array()

$search_array = array('user_from','lucky_draw_id','prize_id');

if (in_array('prize_id', $search_array)) {
    echo "The 'prize_id' element is in the array";
}

Here is output: The 'prize_id' element is in the array

Using: array_key_exists()

$search_array = array('user_from','lucky_draw_id','prize_id');

if (array_key_exists('prize_id', $search_array)) {
    echo "The 'prize_id' element is in the array";
}

No output

In conclusion, array_key_exists() does not work with a simple array. Its only to find whether an array key exist or not. Use in_array() instead.

Here is more example:

<?php
/**++++++++++++++++++++++++++++++++++++++++++++++
 * 1. example with assoc array using in_array
 *
 * IMPORTANT NOTE: in_array is case-sensitive
 * in_array — Checks if a value exists in an array
 *
 * DOES NOT WORK FOR MULTI-DIMENSIONAL ARRAY
 *++++++++++++++++++++++++++++++++++++++++++++++
 */
$something = array('a' => 'bla', 'b' => 'omg');
if (in_array('omg', $something)) {
    echo "|1| The 'omg' value found in the assoc array ||";
}

/**++++++++++++++++++++++++++++++++++++++++++++++
 * 2. example with index array using in_array
 *
 * IMPORTANT NOTE: in_array is case-sensitive
 * in_array — Checks if a value exists in an array
 *
 * DOES NOT WORK FOR MULTI-DIMENSIONAL ARRAY
 *++++++++++++++++++++++++++++++++++++++++++++++
 */
$something = array('bla', 'omg');
if (in_array('omg', $something)) {
    echo "|2| The 'omg' value found in the index array ||";
}

/**++++++++++++++++++++++++++++++++++++++++++++++
 * 3. trying with array_search
 *
 * array_search — Searches the array for a given value 
 * and returns the corresponding key if successful
 *
 * DOES NOT WORK FOR MULTI-DIMENSIONAL ARRAY
 *++++++++++++++++++++++++++++++++++++++++++++++
 */
$something = array('a' => 'bla', 'b' => 'omg');
if (array_search('bla', $something)) {
    echo "|3| The 'bla' value found in the assoc array ||";
}

/**++++++++++++++++++++++++++++++++++++++++++++++
 * 4. trying with isset (fastest ever)
 *
 * isset — Determine if a variable is set and 
 * is not NULL
 *++++++++++++++++++++++++++++++++++++++++++++++
 */
$something = array('a' => 'bla', 'b' => 'omg');
if($something['a']=='bla'){
    echo "|4| Yeah!! 'bla' found in array ||";
}

/**
 * OUTPUT:
 * |1| The 'omg' element value found in the assoc array ||
 * |2| The 'omg' element value found in the index array ||
 * |3| The 'bla' element value found in the assoc array ||
 * |4| Yeah!! 'bla' found in array ||
 */
?>

Here is PHP DEMO

You can use:

• array_search()
• in_array()
• a combination of array_flip() and array_key_exists()

in_array() is fine if you're only checking but if you need to check that a value exists and return the associated key, array_search is a better option.

$data = [
    'hello',
    'world'
];

$key = array_search('world', $data);

if ($key) {
    echo 'Key is ' . $key;
} else {
    echo 'Key not found';
}

This will print "Key is 1"

To check if the index is defined: isset($something['say'])

You can test whether an array has a certain element at all or not with isset() or sometimes even better array_key_exists() (the documentation explains the differences). If you can't be sure if the array has an element with the index 'say' you should test that first or you might get 'warning: undefined index....' messages.

As for the test whether the element's value is equal to a string you can use == or (again sometimes better) the identity operator === which doesn't allow type juggling.

if( isset($something['say']) && 'bla'===$something['say'] ) {
  // ...
}

Just use the PHP function array_key_exists()

<?php
$search_array = array('first' => 1, 'second' => 4);
if (array_key_exists('first', $search_array)) {
    echo "The 'first' element is in the array";
}
?>

<?php
if (in_array('your_variable', $Your_array)) {
    $redImg = 'true code here';
} else {
    $redImg = 'false code here';
} 
?>

Well, first off an associative array can only have a key defined once, so this array would never exist. Otherwise, just use in_array() to determine if that specific array element is in an array of possible solutions.

bool in_array ( mixed $needle , array $haystack [, bool $strict = FALSE ] )

Another use of in_array in_array() with an array as needle

<?php
$a = array(array('p', 'h'), array('p', 'r'), 'o');

if (in_array(array('p', 'h'), $a)) {
    echo "'ph' was found\n";
}

if (in_array(array('f', 'i'), $a)) {
    echo "'fi' was found\n";
}

if (in_array('o', $a)) {
    echo "'o' was found\n";
}
?>

Assuming you are using a simple array

. i.e.

$MyArray = array("red","blue","green");

You can use this function

function val_in_arr($val,$arr){
  foreach($arr as $arr_val){
    if($arr_val == $val){
      return true;
    }
  }
  return false;
}

Usage:

val_in_arr("red",$MyArray); //returns true
val_in_arr("brown",$MyArray); //returns false