I am trying to print a string with a uint64 but no combination of strconv methods that I use is working.
log.Println("The amount is: " + strconv.Itoa((charge.Amount)))
Gives me:
cannot use charge.Amount (type uint64) as type int in argument to strconv.Itoa
How can I print this string?
6 Answers
strconv.Itoa() expects a value of type int, so you have to give it that:
log.Println("The amount is: " + strconv.Itoa(int(charge.Amount)))
But know that this may lose precision if int is 32-bit (while uint64 is 64), also sign-ness is different. strconv.FormatUint() would be better as that expects a value of type uint64:
log.Println("The amount is: " + strconv.FormatUint(charge.Amount, 10))
For more options, see this answer: Golang: format a string without printing?
If your purpose is to just print the value, you don't need to convert it, neither to int nor to string, use one of these:
log.Println("The amount is:", charge.Amount)
log.Printf("The amount is: %d\n", charge.Amount)
if you want to convert int64 to string, you can use :
strconv.FormatInt(time.Now().Unix(), 10)
or
strconv.FormatUint
If you actually want to keep it in a string you can use one of Sprint functions. For instance:
myString := fmt.Sprintf("%v", charge.Amount)
func main() {
var a uint64
a = 3
var s string
s = fmt.Sprint(a)
fmt.Printf("%s", s)
}
log.Printf("The amount is: %d\n", charge.Amount)
If you came here looking on how to covert string to uint64, this is how its done:
newNumber, err := strconv.ParseUint("100", 10, 64)
