I know that print(e) (where e is an Exception) prints the occurred exception
but, I was trying to find the python equivalent of Java's e.printStackTrace() that exactly traces the exception to what line it occurred and prints the entire trace of it.
Could anyone please tell me the equivalent of e.printStackTrace() in Python?
4 Answers
import traceback
traceback.print_exc()
When doing this inside an except ...: block it will automatically use the current exception. See for more information.
There is also logging.exception.
import logging
...
try:
g()
except Exception as ex:
logging.exception("Something awful happened!")
# will print this message followed by traceback
Output:
ERROR 2007-09-18 23:30:19,913 error 1294 Something awful happened!
Traceback (most recent call last):
File "b.py", line 22, in f
g()
File "b.py", line 14, in g
1/0
ZeroDivisionError: integer division or modulo by zero
(From via How to print the full traceback without halting the program?)
e.printStackTrace equivalent in python
In Java, this does the following (docs):
public void printStackTrace()Prints this throwable and its backtrace to the standard error stream...
This is used like this:
try
{
// code that may raise an error
}
catch (IOException e)
{
// exception handling
e.printStackTrace();
}
In Java, the Standard Error stream is unbuffered so that output arrives immediately.
The same semantics in Python 2 are:
import traceback
import sys
try: # code that may raise an error
pass
except IOError as e: # exception handling
# in Python 2, stderr is also unbuffered
print >> sys.stderr, traceback.format_exc()
# in Python 2, you can also from __future__ import print_function
print(traceback.format_exc(), file=sys.stderr)
# or as the top answer here demonstrates, use:
traceback.print_exc()
# which also uses stderr.
