I'm having a small problem trying to malloc this struct. Here is the code for the structure:
typedef struct stats {
int strength;
int wisdom;
int agility;
} stats;
typedef struct inventory {
int n_items;
char **wepons;
char **armor;
char **potions;
char **special;
} inventory;
typedef struct rooms {
int n_monsters;
int visited;
struct rooms *nentry;
struct rooms *sentry;
struct rooms *wentry;
struct rooms *eentry;
struct monster *monsters;
} rooms;
typedef struct monster {
int difficulty;
char *name;
char *type;
int hp;
} monster;
typedef struct dungeon {
char *name;
int n_rooms;
rooms *rm;
} dungeon;
typedef struct player {
int maxhealth;
int curhealth;
int mana;
char *class;
char *condition;
stats stats;
rooms c_room;
} player;
typedef struct game_structure {
player p1;
dungeon d;
} game_structure;
And here is the code I'm having a problem with:
dungeon d1 = (dungeon) malloc(sizeof(dungeon));
It gives me the error "error: conversion to non-scalar type requested" Can someone help me understand why this is?
3 Answers
You can't cast anything to a structure type. What I presume you meant to write is:
dungeon *d1 = (dungeon *)malloc(sizeof(dungeon));
But please don't cast the return value of malloc() in a C program.
dungeon *d1 = malloc(sizeof(dungeon));
Will work just fine and won't hide #include bugs from you.
malloc returns a pointer, so probably what you want is the following:
dungeon* d1 = malloc(sizeof(dungeon));
Here is what malloc looks like:
void *malloc( size_t size );
As you can see it return void*, however you shouldn't cast the return value.
The memory assigned by malloc must be stored in a pointer to an object, not in the object itself:
dungeon *d1 = malloc(sizeof(dungeon));
