I want to use CASE in my stored procedure. I am getting some syntax error in my code:
select
case @Temp
when 1 then (@selectoneCount=@selectoneCount+1)
when 2 then (@selectoneCount=@selectoneCount+1)
end
When running, I'm getting:
incorrect syntax near '='.
at this line here:
@selectoneCount = @selectoneCount + 1
near the equal.
Actually I am getting return value from a another sp into @temp and then if @temp =1 then I want to increment the count of @SelectoneCount by 1 and so on. Please let me know what is the correct syntax.
4 Answers
The CASE is just a "switch" to return a value - not to execute a whole code block.
You need to change your code to something like this:
SELECT
@selectoneCount = CASE @Temp
WHEN 1 THEN @selectoneCount + 1
WHEN 2 THEN @selectoneCount + 1
END
If @temp is set to none of those values (1 or 2), then you'll get back a NULL
This is a select statement, so each branch of the case must return something. If you want to perform actions, just use an if.
select
@selectoneCount = case @Temp
when 1 then (@selectoneCount+1)
when 2 then (@selectoneCount+1)
end
select @selectoneCount
Actually i am getting return value from a another sp into @temp and then it @temp =1 then i want to inc the count of @SelectoneCount by 1 and so on. Please let me know what is the correct syntax.
What's wrong with:
IF @Temp = 1 --Or @Temp = 2 also?
BEGIN
SET @SelectoneCount = @SelectoneCount + 1
END
(Although this does reek of being procedural code - not usually the best way to use SQL)
