this is my code:
print str(float(1/3))+'%'
and it shows:
0.0%
but I want to get 33%
What can I do?
7 Answers
format supports a percentage floating point precision type:
>>> print "{0:.0%}".format(1./3)
33%
If you don't want integer division, you can import Python3's division from __future__:
>>> from __future__ import division
>>> 1 / 3
0.3333333333333333
# The above 33% example would could now be written without the explicit
# float conversion:
>>> print "{0:.0f}%".format(1/3 * 100)
33%
# Or even shorter using the format mini language:
>>> print "{:.0%}".format(1/3)
33%
There is a way more convenient 'percent'-formatting option for the .format() format method:
>>> '{:.1%}'.format(1/3.0)
'33.3%'
Just for the sake of completeness, since I noticed no one suggested this simple approach:
>>> print("%.0f%%" % (100 * 1.0/3))
33%
Details:
%.0fstands for "print a float with 0 decimal places", so%.2fwould print33.33%%prints a literal%. A bit cleaner than your original+'%'1.0instead of1takes care of coercing the division to float, so no more0.0
Just to add Python 3 f-string solution
prob = 1.0/3.0
print(f"{prob:.0%}")
You are dividing integers then converting to float. Divide by floats instead.
As a bonus, use the awesome string formatting methods described here:
To specify a percent conversion and precision.
>>> float(1) / float(3)
[Out] 0.33333333333333331
>>> 1.0/3.0
[Out] 0.33333333333333331
>>> '{0:.0%}'.format(1.0/3.0) # use string formatting to specify precision
[Out] '33%'
>>> '{percent:.2%}'.format(percent=1.0/3.0)
[Out] '33.33%'
A great gem!
Then you'd want to do this instead:
print str(int(1.0/3.0*100))+'%'
The .0 denotes them as floats and int() rounds them to integers afterwards again.
I use this
ratio = round(1/3, 2)
print(f"{ratio} %")
output: 0.33 %
