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I'm working on making a menu in python that needs to:
- Print out a menu with numbered options
- Let the user enter a numbered option
- Depending on the option number the user picks, run a function specific to that action. For now, your function can just print out that it's being run.
- If the user enters in something invalid, it tells the user they did so, and re-display the menu
- use a dictionary to store menu options, with the number of the option as the key, and the text to display for that option as the value.
- The entire menu system should run inside a loop and keep allowing the user to make choices until they select exit/quit, at which point your program can end.
I'm new to Python, and I can't figure out what I did wrong with the code.
So far this is my code:
ans=True
while ans:
print (""""
1.Add a Student
2.Delete a Student
3.Look Up Student Record
"""")
ans=input("What would you like to do?"
if ans=="1":
print("\nStudent Added")
elif ans=="2":
print("\n Student Deleted")
elif ans=="3":
print("\n Student Record Found")
elif ans=="4":
print("\n Goodbye")
elif ans !="":
print("\n Not Valid Choice Try again")
ANSWERED
This is what he wanted apparently:
menu = {}
menu['1']="Add Student."
menu['2']="Delete Student."
menu['3']="Find Student"
menu['4']="Exit"
while True:
options=menu.keys()
options.sort()
for entry in options:
print entry, menu[entry]
selection=raw_input("Please Select:")
if selection =='1':
print "add"
elif selection == '2':
print "delete"
elif selection == '3':
print "find"
elif selection == '4':
break
else:
print "Unknown Option Selected!"
4 Answers
def my_add_fn():
print "SUM:%s"%sum(map(int,raw_input("Enter 2 numbers seperated by a space").split()))
def my_quit_fn():
raise SystemExit
def invalid():
print "INVALID CHOICE!"
menu = {"1":("Sum",my_add_fn),
"2":("Quit",my_quit_fn)
}
for key in sorted(menu.keys()):
print key+":" + menu[key][0]
ans = raw_input("Make A Choice")
menu.get(ans,[None,invalid])[1]()
There were just a couple of minor amendments required:
ans=True
while ans:
print ("""
1.Add a Student
2.Delete a Student
3.Look Up Student Record
""")
ans=raw_input("What would you like to do? ")
if ans=="1":
print("\n Student Added")
elif ans=="2":
print("\n Student Deleted")
elif ans=="3":
print("\n Student Record Found")
elif ans=="4":
print("\n Goodbye")
elif ans !="":
print("\n Not Valid Choice Try again")
I have changed the four quotes to three (this is the number required for multiline quotes), added a closing bracket after "What would you like to do? " and changed input to raw_input.
This should do it. You were missing a ) and you only need """ not 4 of them. Also you don't need a elif at the end.
ans=True
while ans:
print("""
1.Add a Student
2.Delete a Student
3.Look Up Student Record
""")
ans=raw_input("What would you like to do? ")
if ans=="1":
print("\nStudent Added")
elif ans=="2":
print("\n Student Deleted")
elif ans=="3":
print("\n Student Record Found")
elif ans=="4":
print("\n Goodbye")
ans = None
else:
print("\n Not Valid Choice Try again")
It looks like you've just finished step 3. Instead of running a function, you just print out a statement. A function is defined in the following way:
def addstudent():
print("Student Added.")
then called by writing addstudent().
I would recommend using a while loop for your input. You can define the menu option outside the loop, put the print statement inside the loop, and do while(#valid option is not picked), then put the if statements after the while. Or you can do a while loop and continue the loop if a valid option is not selected.
Additionally, a dictionary is defined in the following way:
my_dict = {key:definition,...}
