I have a school project and I have to use the AM in the Student.h as a char*.The AM have to have numbers in it. I can't understand why what I am doing is not working. Student.cpp
#include <iostream>
#include <string>
#include "Student.h"
using namespace std;
int main()
{
Student dlg;
dlg.AM[10]={2,1,3,9,0,2,6,6};
}
Student.h
#pragma once
#include <string>
using namespace std;
class Student
{
public:
char *AM[20];
string Name;
unsigned int Semester = 1;
};
1 Answer
If you really need your student number to be a char string, then you need to convert your ints to char* before assigning them to the array.
int main()
{
Student dlg;
int j = 0;
for (auto i : {2,1,3,9,0,2,6,6})
{
auto strInt { std::to_string(i) }; // create a C++ string containing a int
// next copy the internal memory of the C++ string to a read-writable memory buffer
// and assign a pointer to that buffer casted to a char* to the appropriate slot in the array
dlg.AM[j++] = static_cast<char*> (std::memcpy (new char[16], strInt.c_str(), strInt.size()));
}
// test
for (int i = 0; i < 8; i++)
{
cout << dlg.AM[i] << ' ';
}
}
Are you sure the student number should be a char* ?
