Improving on @alecxe's answer: if you use a Python Generator and a requests HTTP session you can improve the performance and resource usage if you are querying lots of pages or very large pages.

import requests

session = requests.Session()

def get_jobs():
    url = "" 
    first_page = session.get(url).json()
    yield first_page
    num_pages = first_page['last_page']

    for page in range(2, num_pages + 1):
        next_page = session.get(url, params={'page': page}).json()
        yield next_page

for page in get_jobs():
    # TODO: process the page

I came across a scenario where the API didn't return pages but rather a min/max value. I created this, and I think it will work for both situations. This will automatically increase the increment until it reaches the end, and then it will stop the while loop.

max_version = [1]
while len(max_version) > 0:
    r = requests.get(url, headers=headers, params={"page": max_version[0]}).json()
    next_page = r['page']
    if next_page is not None:
        max_version[0] = next_page
        Process data...
    else:
        max_version.clear() # Stop the while loop

Further improving on @dh762 's answer, you can use while and have all the requests done in it without having 2 yield statements.

Eg:

import requests

session = requests.Session()

def get_jobs():
    url = ""
    currP = 1
    totalP = 2 #assuming there's gonna be 2nd page, it'll get overwritten if not.
    while (currP <= totalP):
        page = session.get(url, params={'page': currP}).json()
        totalP = page['last_page']
        currP += 1
        yield page

for page in get_jobs():
    # TODO: process the page

Here is what worked for me, using **extraArgs

# our initial url
url = f'{base_url}/{api_endpoint}'

# we set a next token, to start our while loop
NextToken = True

# we specify our extra args object
extraArgs = {
    "url": url,
    "headers": headers
}

while NextToken is not None:
    # call api
    r = requests.get(**extraArgs)
    result = r.json()

    # if next url exists, add to method arguments, and do next call with it
    if 'next' in result['_links']:
        next_link = result['_links']['next']['href']
        print(f'found next link: {next_link}')
        extraArgs['url'] = next_link
    else:
        break

If you have to pull data from HTTP API that has an endpoint accepting parameters:

pageNumber=1,2,...

And returning JSON:

{
    "pageCount": 5,
    "entities": [
      {"key":  "val1", ...},
      {"key":  "val2", ...},
      ...
    ]
}

Then you can iterate over all pages with following code (after running pip3 install bezalel):

import requests
from bezalel import PaginatedApiIterator

for page in PaginatedApiIterator(requests.Session(), url=f"",
                                                   request_page_number_param_name="pageNumber",
                                                   response_page_count_field_name="pageCount",
                                                   response_records_field_name="entities"):
    print(f"Page: {page}")

It will print:

Page: [{"key":  "val1", ...}, {"key":  "val2", ...}, ...]
Page: [{"key":  "val100", ...}, {"key":  "val101", ...}, ...]
Page: [{"key":  "val200", ...}, {"key":  "val201", ...}, ...]
...

More docs: