I am creating a form to lookup the details of a support request in our call logging system.
Call references are assigned a number like F0123456 which is what the user would enter, but the record in the database would be 123456. I have the following code for collecting the data from the form before submitting it with jQuery ajax.
How would I strip out the leading F0 from the string if it exists?
$('#submit').click(function () {
var rnum = $('input[name=rnum]');
var uname = $('input[name=uname]');
var url = 'rnum=' + rnum.val() + '&uname=' + uname.val();
6 Answers
Simply replace it with nothing:
var string = 'F0123456'; // just an example
string.replace(/^F0+/i, ''); '123456'
Honestly I think this probably the most concise and least confusing, but maybe that is just me:
str = "F0123456";
str.replace("f0", "");
Dont even go the regular expression route and simply do a straight replace.
Another way to do it:
rnum = rnum.split("F0").pop()
It splits the string into two: ["", "123456"], then selects the last element.
If you want to remove F0 from the whole string then the replaceAll() method works for you.
const str = 'F0123F0456F0'.replaceAll('F0', '');
console.log(str);Regexp solution:
ref = ref.replace(/^F0/, "");
plain solution:
if (ref.substr(0, 2) == "F0")
ref = ref.substr(2);
if it is not the first two chars and you wanna remove F0 from the whole string then you gotta use this regex
let string = 'F0123F0456F0';
let result = string.replace(/F0/ig, '');
console.log(result);
