I can't resolve my problem, this is the error from mysql that I'm getting:
I can edit and update my data when I've got one record in the database but when I add two rows, I get the error.
Some pictures from database
And when I change the row, row ID goes down to 0 and that's is a problem as I can't edit other rows.
CREATE TABLE `dati` (
`ID` int(11) NOT NULL AUTO_INCREMENT,
`title` varchar(255) NOT NULL,
`value1` varchar(255) NOT NULL,
`value2` varchar(255) NOT NULL,
PRIMARY KEY (`ID`)
) ENGINE=InnoDB AUTO_INCREMENT=3 DEFAULT CHARSET=latin1 PACK_KEYS=1
Update Code:
<?php // Izlabot datus datubāzē!
$titletxt = $_POST['title_edit'];
$value1 = $_POST['value1_edit'];
$value2 = $_POST['value2_edit'];
if(isset($_POST['edit'])){
$con=mysqli_connect("localhost","root","","dbname");
if (mysqli_connect_errno())
{
echo "Neizdevās savienoties ar MySQL: " . mysqli_connect_error();
}
$sql="UPDATE dati SET ID='$ID',title= '$titletxt',value1='$value1',value2='$value2' WHERE 1";
if (!mysqli_query($con,$sql))
{
die('Error: ' . mysqli_error($con));
}
echo '<script>
alert(" Ieraksts ir veiksmīgi labots! ");
window.location.href = "index.php";
</script>';
mysqli_close($con);
}
?>
From form:
<?php
$con=mysqli_connect("localhost","root","","dbname");
if (mysqli_connect_errno())
{
echo "Neizdevās savienoties ar MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($con,"SELECT * FROM dati");
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td><input id='titled' type='text' name='title_edit' value='" . $row['title'] . "'></td>";
echo "<td><input id='value1d' type='text' name='value1_edit' value='" . $row['value1'] . "'></td>";
echo "<td><input id='value2d' type='text' name='value2_edit' value='" . $row['value2'] . "'></td>";
echo "<input type='hidden' name='id' value='" . $row['ID'] . "'>";
echo "<td><button name='edit' id='edit_btn' class='frm_btns' value='" . $row['ID'] . "'>Edit</button></td>";
echo "</tr>";
}
mysqli_close($con);
?>
It couldn't read the value of ID, as 0 was returned.
8 Answers
For those arriving at this question because of the question title (as I did), this solved my problem:
This error can indicate that the table's PRIMARY KEY is not set to AUTO-INCREMENT, (and your insert query did not specify an ID value).
To resolve:
Check that there is a PRIMARY KEY set on your table, and that the PRIMARY KEY is set to AUTO-INCREMENT.
How to add auto-increment to column in mysql database using phpmyadmin?
The problem is that your code attempts to change every row in the data changing the primary key to the value in $ID. This is not set anywhere in your code, and presumably is being cast as 0
$sql="UPDATE `dati` SET `ID`='$ID',`title`=
'$titletxt',`value1`='$value1',`value2`='$value2' WHERE 1";
The primary key value should be sent to the form and returned so it can be processed by your code, but the value should be retained, hence....
$sql="UPDATE `dati` SET `title`=
'$titletxt',`value1`='$value1',`value2`='$value2' WHERE `ID`=$ID";
You should also read up on MySQL injection - even after you've fixed the errors here, anyone can do just about anything they want with your database.
The error log like (In my case), I'm using Aurora DB:
PHP message: WordPress database error Duplicate entry '0' for key 'PRIMARY' for query INSERT INTO `date173_postmeta
How to fix it using MySQL Workbench:
1- Connect at your DB, and go to the table with the issue, in my case date173_postmeta
2- Select the tools icon:
3- In the windows/tab at right, select the AI checkbox and click on Apply button:
Following the last steps my issues gone.
Try this:
ID int(11) PRIMARY KEY AUTOINCREMENT(1,3)
The problem in set ID = $ID
Try removing it so the code should be
$sql="UPDATE `dati` `title`= '$titletxt',`value1`='$value1',`value2`='$value2' WHERE 1";
Be sure to change this where cause it'll update ever row with these values
Just make sure that your primery keys are also A-I.
I'd been struggling to fix this. My tables had auto increment (AI) switched on Before I started tinkering with records I tried a simple repair in phpMyAdmin. Go to the SQL tab and run each command in turn.
REPAIR TABLE wp_options REPAIR TABLE wp_users REPAIR TABLE wp_usermeta
This did the trick for me and allowed me to login.
i am using phpmyadmin, so go to db , search for wp_postmeta tabel add AI(auto-increment) to meta_id save the changes
