I have a doubt regarding how equals() method works for ArrayList. The below code snippet prints true.
ArrayList<String> s = new ArrayList<String>();
ArrayList<Integer> s1 = new ArrayList<Integer>();
System.out.println(s1.equals(s));
Why does it print true?
4 Answers
Look the doc for the equals() method of ArrayList
Returns true if and only if the specified object is also a list, both lists have the same size, and all corresponding pairs of elements in the two lists are equal.
Since there are no elements, all the conditions satisfied and hence true.
If you add elements to the both list (atleast one in each), to see the desired output.
The contract of the List.equals is that two lists are equal if all their elements are equal (in terms of equals()). Here, both are empty lists, so they are equal. The generic type is irrelevant, as there are anyway no list elements to compare.
However, they are not equal in terms of == as these are two different objects.
See this question for details between equals() and ==
Here is the ArrayList implementation of the equals method from the AbstractList with a few commments what it actually does:
public boolean equals(Object o) {
if (o == this) // Not the same list so no return
return true;
if (!(o instanceof List)) // is an instance of List, so no return
return false;
ListIterator<E> e1 = listIterator();
ListIterator<?> e2 = ((List<?>) o).listIterator();
while (e1.hasNext() && e2.hasNext()) { // Both have no next, so no loop here
E o1 = e1.next();
Object o2 = e2.next();
if (!(o1==null ? o2==null : o1.equals(o2)))
return false;
}
return !(e1.hasNext() || e2.hasNext()); // Both validate to false, so negating false return true in the end.
}
As previous answers pointed, equals returns true because both objects are instances of List and have the same size (0).
It's also worth mentioning that the fact that one List contains Integer and the other String does not affect the behaviour because of type erasure in Java.
