Im in no way an experienced python programmer,thats why i believe there may be an obvious answer to this but i just can't wrap my head around the struct.pack and unpack. i have the following code:
struct.pack("<"+"I"*elements, *self.buf[:elements])
I want to reverse the the packing of this, however im not sure how, i know that "<" means little endian and "I" is unsigned int and thats about it, im not sure how to use struct.unpack to reverse the packing.
2 Answers
struct.pack takes non-byte values (e.g. integers, strings, etc.) and converts them to bytes. And conversely, struct.unpack takes bytes and converts them to their 'higher-order' equivalents.
For example:
>>> from struct import pack, unpack
>>> packed = pack('hhl', 1, 2, 3)
>>> packed
b'\x00\x01\x00\x02\x00\x00\x00\x03'
>>> unpacked = unpack('hhl', packed)
>>> unpacked
(1, 2, 3)
So in your instance, you have little-endian unsigned integers (elements many of them). You can unpack them using the same structure string (the '<' + 'I' * elements part) - e.g. struct.unpack('<' + 'I' * elements, value).
Example from:
Looking at the documentation:
obj = struct.pack("<"+"I"*elements, *self.buf[:elements])
struct.unpack("<"+"I"*elements, obj)
Does this work for you?
