How can I write the following list:
[(8, 'rfa'), (8, 'acc-raid'), (7, 'rapidbase'), (7, 'rcts'), (7, 'tve-announce'), (5, 'mysql-im'), (5, 'telnetcpcd'), (5, 'etftp'), (5, 'http-alt')]
to a text file with two columns (8 rfa) and many rows, so that I have something like this:
8 rfa
8 acc-raid
7 rapidbase
7 rcts
7 tve-announce
5 mysql-im
5 telnetcpcd
7 Answers
with open('daemons.txt', 'w') as fp:
fp.write('\n'.join('%s %s' % x for x in mylist))
If you want to use str.format(), replace 2nd line with:
fp.write('\n'.join('{} {}'.format(x[0],x[1]) for x in mylist))
import csv
with open(<path-to-file>, "w") as the_file:
csv.register_dialect("custom", delimiter=" ", skipinitialspace=True)
writer = csv.writer(the_file, dialect="custom")
for tup in tuples:
writer.write(tup)
The csv module is very powerful!
open('filename', 'w').write('\n'.join('%s %s' % x for x in mylist))
Here is the third way that I came up with:
for number, letter in myList:
of.write("\n".join(["%s %s" % (number, letter)]) + "\n")
simply convert the tuple to string with str()
f=open("filename.txt","w+")
# in between code
f.write(str(tuple)+'/n')
# continue
For flexibility, for example; if some items in your list contain 3 items, others contain 4 items and others contain 2 items you can do this.
mylst = [(8, 'rfa'), (8, 'acc-raid','thrd-item'), (7, 'rapidbase','thrd-item','fourth-item'),(9, 'tryrt')]
# this function converts the integers to strings with a space at the end
def arrtostr(item):
strr=''
for b in item:
strr+=str(b)+' '
return strr
# now write to your file
with open('list.txt','w+') as doc:
for line in mylst:
doc.write(arrtostr(line)+'\n')
doc.close()
And the output in list.txt
8 rfa
8 acc-raid thrd-item
7 rapidbase thrd-item fourth-item
9 tryrt
After adding f-strings in Python you can use this example:
mylst = [(8, 'rfa'), (8, 'acc-raid'), (7, 'rapidbase'), (7, 'rcts'), (7, 'tve-announce'), (5, 'mysql-im')]
f = open('out.txt', mode='w+')
for elem in mylst:
f.write(f'{elem}\n')
