In python3, how do I match exactly whitespace character and not newline \n or tab \t?
I've seen the \s+[^\n] answer from Regex match space not \n answer, but for the following example it does not work:
a='rasd\nsa sd'
print(re.search(r'\s+[^ \n]',a))
Result is <_sre.SRE_Match object; span=(4, 6), match='\ns'>, which is the newline matched.
2 Answers
No need for special groups. Just create a regex with a space character. The space character does not have any special meaning, it just means "match a space".
RE = re.compile(' +')
So for your case
a='rasd\nsa sd'
print(re.search(' +', a))
would give
<_sre.SRE_Match object; span=(7, 8), match=' '>
If you want to match 1 or more whitespace chars except the newline and a tab use
r"[^\S\n\t]+"
The [^\S] matches any char that is not a non-whitespace = any char that is whitespace. However, since the character class is a negated one, when you add characters to it they are excluded from matching.
import re
a='rasd\nsa sd'
print(re.findall(r'[^\S\n\t]+',a))
# => [' ']
Some more considerations: \s matches [ \t\n\r\f\v] if ASCII flag is used. So, if you plan to only match ASCII, you might as well use [ \r\f\v] to exclude the chars you want. If you need to work with Unicode strings, the solution above is a viable one.
