I am trying to sort a nested list in python(3.8.5). I have a list like -
[['1', 'A', 2, 5, 45, 10],
['2', 'B', 8, 15, 65, 20],
['3', 'C', 32, 35, 25, 140],
['4', 'D', 82, 305, 75, 90],
['5', 'E', 39, 43, 89, 55],
]
and I want to sort like this -
[['4', 'D', 82, 305, 75, 90],
['5', 'E', 39, 43, 89, 55],
['3', 'C', 32, 35, 25, 140],
['2', 'B', 8, 15, 65, 20],
['1', 'A', 2, 5, 45, 10],
]
it has sorted by column with index 2. and more like this according to index. start with index 2 and so on. I mean it has sorted according to columns. so could I do this.
3 Answers
Try this:
lst = [['1', 'A', 2, 5, 45, 10],
['2', 'B', 8, 15, 65, 20],
['3', 'C', 32, 35, 25, 140],
['4', 'D', 82, 305, 75, 90],
['5', 'E', 39, 43, 89, 55],
]
lst = sorted(lst, key=lambda x: x[2], reverse=True)
print(lst)
If you want to sort a list like that, just give sorted a key:
sorted_list = sorted([['1', 'A', 2, 5, 45, 10],
['2', 'B', 8, 15, 65, 20],
['3', 'C', 32, 35, 25, 140],
['4', 'D', 82, 305, 75, 90],
['5', 'E', 39, 43, 89, 55]], key=lambda lst: lst[2], lst[1], ....)
For numerical values, you can even include a negative sign (-lst[1]) to reverse the ordering for an individual column
Code to sort the tuples using second element of sub-list in-place way to sort using sort():
def sort(sub_li):
# reverse = None (Sorts in Ascending order)
# key is set to sort using second element of
# sublist lambda has been used
sub_li.sort(key = lambda x: x[2],reverse=True)
return sub_li
# Driver Code
sub_li =[['1', 'A', 2, 5, 45, 10],
['2', 'B', 8, 15, 65, 20],
['3', 'C', 32, 35, 25, 140],
['4', 'D', 82, 305, 75, 90],
['5', 'E', 39, 43, 89, 55],
]
print(Sort(sub_li))
