Is the function I wrote below enough to preload images in most, if not all, browsers commonly used today?
function preloadImage(url)
{
var img=new Image();
img.src=url;
}
I have an array of image URLs that I loop over and call the preloadImage function for each URL.
18 Answers
Yes. This should work on all major browsers.
Try this I think this is better.
var images = [];
function preload() {
for (var i = 0; i < arguments.length; i++) {
images[i] = new Image();
images[i].src = preload.arguments[i];
}
}
//-- usage --//
preload(
"",
"",
""
)
Source:
In my case it was useful to add a callback to your function for onload event:
function preloadImage(url, callback)
{
var img=new Image();
img.src=url;
img.onload = callback;
}
And then wrap it for case of an array of URLs to images to be preloaded with callback on all is done:
function preloadImages(urls, allImagesLoadedCallback){
var loadedCounter = 0;
var toBeLoadedNumber = urls.length;
urls.forEach(function(url){
preloadImage(url, function(){
loadedCounter++;
console.log('Number of loaded images: ' + loadedCounter);
if(loadedCounter == toBeLoadedNumber){
allImagesLoadedCallback();
}
});
});
function preloadImage(url, anImageLoadedCallback){
var img = new Image();
img.onload = anImageLoadedCallback;
img.src = url;
}
}
// Let's call it:
preloadImages([
'//
'//
], function(){
console.log('All images were loaded');
});
You can move this code to index.html for preload images from any url
<link rel="preload" href="" as="image">
const preloadImage = src =>
new Promise(r => {
const image = new Image()
image.onload = r
image.onerror = r
image.src = src
})
// Preload an image
await preloadImage(')
// Preload a bunch of images in parallel
await Promise.all(images.map(x => preloadImage(x.src)))
CSS2 Alternative:
body:after {
content: url(img01.jpg) url(img02.jpg) url(img03.jpg);
display: none;
}
CSS3 Alternative: (H/T Linh Dam)
.preload-images {
display: none;
width: 0;
height: 0;
background: url(img01.jpg),
url(img02.jpg),
url(img03.jpg);
}
NOTE: Images in a container with display:none might not preload.
Perhaps visibility:hidden will work better but I have not tested this. Thanks Marco Del Valle for pointing this out
I recommend you use a try/catch to prevent some possible issues:
OOP:
var preloadImage = function (url) {
try {
var _img = new Image();
_img.src = url;
} catch (e) { }
}
Standard:
function preloadImage (url) {
try {
var _img = new Image();
_img.src = url;
} catch (e) { }
}
Also, while I love DOM, old stupid browsers may have problems with you using DOM, so avoid it altogether IMHO contrary to freedev's contribution. Image() has better support in old trash browsers.
This approach is a little more elaborate. Here you store all preloaded images in a container, may be a div. And after you could show the images or move it within the DOM to the correct position.
function preloadImg(containerId, imgUrl, imageId) {
var i = document.createElement('img'); // or new Image()
i.id = imageId;
i.onload = function() {
var container = document.getElementById(containerId);
container.appendChild(this);
};
i.src = imgUrl;
}
Try it here, I have also added few comments
Working solution as of 2020
Most answers on this post no longer work - (atleast on Firefox)
Here's my solution:
var cache = document.createElement("CACHE");
cache.style = "position:absolute;z-index:-1000;opacity:0;";
document.body.appendChild(cache);
function preloadImage(url) {
var img = new Image();
img.src = url;
img.style = "position:absolute";
cache.appendChild(img);
}
Usage:
preloadImage("");
Obviously <cache> is not a "defined" element, so you could use a <div> if you wanted to.
Use this in your CSS, instead of applying the style attribute:
cache {
position: absolute;
z-index: -1000;
opacity: 0;
}
cache image {
position: absolute;
}
If you have tested this, please leave a comment.
Notes:
- Do NOT apply
display: none;to cache - this will not load the image. - Don't resize the image element, as this will also affect the quality of the loaded image when you come to use it.
- Setting
position: absoluteto the image is necessary, as the image elements will eventually make it's way outside of the viewport - causing them to not load, and affect performance.