I have a PHP file that tries to echo a $_POST and I get an error, here is the code:
echo "<html>";
echo "<body>";
for($i=0; $i<5;$i++){
echo "<input name='C[]' value='$Texting[$i]' " .
"style='background-color:#D0A9F5;'></input>";
}
echo "</body>";
echo "</html>";
echo '<input type="submit" value="Save The Table" name="G"></input>'
Here is the code to echo the POST.
if(!empty($_POST['G'])){
echo $_POST['C'];
}
But when the code runs I get an error like:
Notice: Array to string conversion in
C:\xampp\htdocs\PHIS\FinalSubmissionOfTheFormPHP.php on line 8
What does this error mean and how do I fix it?
5 Answers
When you have many HTML inputs named C[] what you get in the POST array on the other end is an array of these values in $_POST['C']. So when you echo that, you are trying to print an array, so all it does is print Array and a notice.
To print properly an array, you either loop through it and echo each element, or you can use print_r.
Alternatively, if you don't know if it's an array or a string or whatever, you can use var_dump($var) which will tell you what type it is and what it's content is. Use that for debugging purposes only.
What the PHP Notice means and how to reproduce it:
If you send a PHP array into a function that expects a string like: echo or print, then the PHP interpreter will convert your array to the literal string Array, throw this Notice and keep going. For example:
php> print(array(1,2,3))
PHP Notice: Array to string conversion in
/usr/local/lib/python2.7/dist-packages/phpsh/phpsh.php(591) :
eval()'d code on line 1
Array
In this case, the function print dumps the literal string: Array to stdout and then logs the Notice to stderr and keeps going.
Another example in a PHP script:
<?php
$stuff = array(1,2,3);
print $stuff; //PHP Notice: Array to string conversion in yourfile on line 3
?>
