I want to print out only a certain line from the output of a command.
Lets take the example of ipconfig command. This returns a lot of lines.
Windows IP Configuration
Wireless LAN adapter Wireless Network Connection:
Connection-specific DNS Suffix . :
Link-local IPv6 Address . . . . . : ab80::456d:123e:5ae5:9ab6%15
IPv4 Address. . . . . . . . . . . : 192.168.1.33
Subnet Mask . . . . . . . . . . . : 255.255.255.0
Default Gateway . . . . . . . . . : 192.168.1.1
Ethernet adapter Local Area Connection:
Media State . . . . . . . . . . . : Media disconnected
Connection-specific DNS Suffix . :
I want to just print say the 11th line.
I tried the following
FOR /F "skip=10 delims=" %G IN ('IPCONFIG') DO @ECHO %G
This skips only the first 10 lines and prints the rest of the lines.
Default Gateway . . . . . . . . . : 192.168.1.1
Ethernet adapter Local Area Connection:
Media State . . . . . . . . . . . : Media disconnected
Connection-specific DNS Suffix . :
How do I print only the 11th line?
2 Answers
Just leave the loop
FOR /F "skip=10 delims=" %G IN ('IPCONFIG') DO @ECHO %G & goto done
:done
edited Get the 11th line in the output of a command from a single command line
for /f "tokens=1,* delims=:" %a in ('ipconfig^|findstr /n "^"^|findstr /l /b /c:"11:"') do echo %b
Execute the command, number the output, retrieve the required line, split the initial number and echo the rest
set "x=1" & for /f "skip=10 delims=" %a in ('ipconfig') do @(if defined x (set "x=" & echo %a))
Set a flag variable, execute the command, skip the first 10 lines and for each line if the flag is set, clean the flag and echo the line
Could I run this in a single command? I mean not through a batch file. yes:
ipconfig |find "Default Gateway"
(runs both on the command line and in a batch file)
