I'm not getting the desire output, re.sub is only replacing the last occurance using python regular expression, please explain me what i"m doing wrong
srr = " "
re.sub("", "", srr)
'image-1CE005XG03'
Desire output without from the above string.
image-1CCCC|image-1VVDD|image-123|image-1CE005XG03
4 Answers
I would use re.findall here, rather than trying to do a replacement to remove the portions you don't want:
src = " "
matches = re.findall(r'https?://www\.\S+#([^|\s]+)', src)
output = '|'.join(matches)
print(output) # image-1CCCC|image-1VVDD|image-123|image-123|image-1CE005XG03
Note that if you want to be more specific and match only Google URLs, you may use the following pattern instead:
https?://www\.google\.\S+#([^|\s]+)
>>> "|".join(re.findall(r'#([^|\s]+)', srr))
'image-1CCCC|image-1VVDD|image-123|image-123|image-1CE005XG03'
Here is another solution,
"|".join(i.split("#")[-1] for i in srr.split("|"))
image-1CCCC|image-1VVDD|image-123|image-123|image-1CE005XG03
Using correct regex in re.sub as suggested in comment above:
import re
srr = " "
print (re.sub(r"\s*https?://[^#\s]*#", "", srr))
Output:
image-1CCCC|image-1VVDD|image-123|image-123|image-1CE005XG03
RegEx Details:
\s*: Match 0 or more whitespaceshttps?: Matchhttporhttps://: Match://[^#\s]*: Match 0 or more of any characters that are not#and whitespace#: Match a#
