I have the following string 02/11/2012 23:11
Is there any way to convert this to the long 021120122311l?
I am trying to map objects to a specific position in an array based on their date created.
4 Answers
you can use a SimpleDateFormat to generate it as a string without any symbol, and then parse the long value using the Long class
SimpleDateFormat s1 = new SimpleDateFormat("dd/MM/yyyy HH:mm");
SimpleDateFormat s2 = new SimpleDateFormat("ddMMyyyyHHmm");
Date d = s1.parse("02/11/2012 23:11");
String s3 = s2.format(d);
System.out.println(s3);
long l = Long.parseLong(s3);
System.out.println(l);
You can try this
SimpleDateFormat simpleDateFormat = new SimpleDateFormat("dd/MM/yyyy hh:mm");
Date inputDate;
try {
inputDate = simpleDateFormat.parse("02/11/2012 23:11");
System.out.println(inputDate.getTime());
} catch (ParseException e) {
e.printStackTrace();
}
ouput:
1351878060000
Try this,
String dateValue = "02/11/2012 23:11";
SimpleDateFormat simpleDateFormat = new SimpleDateFormat("dd/MM/yyyy HH:mm");
Date date = simpleDateFormat.parse(dateValue);
simpleDateFormat = new SimpleDateFormat("ddMMyyyyHHmm");
String value = simpleDateFormat.format(date);
Long result = Long.parseLong(value);
System.out.println("Result : "+result);
Time zone is critical to parsing a string into a date-time value unless you absolutely sure all the strings represent date-times occurring in the same time zone.
Joda-Time makes this work much easier.
DateTimeFormatter formatter = DateTimeFormat.forPattern( "dd/MM/yyyy hh:mm" );
DateTimeZone timeZone = DateTimeZone.forID( "Europe/Paris" );
DateTime dateTime = formatter.withZone( timeZone ).parseDateTime( myString );
long millisecondsSinceEpoch = dateTime.getMillis();
