I'm new to javascript which should be really simple to solve, but I am lost as of now.
I have a url: http:getall.json Using JavaScript (not JQuery or php. Just JavaScript), I want to read this JSON string and parse it. That's it.
3 Answers
access to your url doesn't work, you should show the JSON result. In javascript to get JSON object with AJAX request you can do something like this:
request = new XMLHttpRequest;
request.open('GET', ' true);
request.onload = function() {
if (request.status >= 200 && request.status < 400){
// Success!
data = JSON.parse(request.responseText);
} else {
// We reached our target server, but it returned an error
}
};
request.onerror = function() {
// There was a connection error of some sort
};
request.send();
your result will be in the data variable.
JSONP calls:
function getJSONP(url, callback) {
var script = document.createElement('script');
var callbackName = "jsonpcallback_" + new Date().getTime();
window[callbackName] = function (json) {
callback(json);
};
script.src = url + (url.indexOf("?") > -1 ? "&" : "?") + 'callback=' + callbackName;
document.getElementsByTagName('head')[0].appendChild(script);
}
getJSONP("", function(jsonObject){
//jsonObject is what you want
});
Regular ajax ajax call:
function getXHR() {
if (window.XMLHttpRequest) {
return new XMLHttpRequest();
}
try {
return new ActiveXObject('MSXML2.XMLHTTP.6.0');
} catch (e) {
try {
// The fallback.
return new ActiveXObject('MSXML2.XMLHTTP.3.0');
} catch (e) {
throw new Error("This browser does not support XMLHttpRequest.");
}
}
}
function getJSON(url, callback) {
req = getXHR();
req.open("GET", url);
req.onreadystatechange = function () {
if (this.readyState == 4 && this.status == 200) {
var jsonObject = null,
status;
try {
jsonObject = JSON.parse(req.responseText);
status = "success";
} catch (e) {
status = "Invalid JSON string[" + e + "]";
}
callback(jsonObject, status, this);
}
};
req.onerror = function () {
callback(null, "error", null);
};
req.send(null);
}
getJSON("", function (jsonObject, status, xhr) {
//jsonObject is what you want
});
I tested these with your url and it seems like you should get the data with a jsonp call, because with regular ajax call it returns:
No 'Access-Control-Allow-Origin' header is present on the requested resource
with jsonp it gets the data but the data is not a valid json, it seems your server side has some php errors:
A PHP Error was encountered
...
In your HTML include your json file and a js code as modules
<script src="/locales/tshared.js" type="module" ></script>
<script src="/scripts/shared.js" type="module" ></script>
file content of tshared
export const loc = '{"en": { "key1": "Welcome" },"pt": {"key1": "Benvindo"} }'
file content of shared
import {loc} from "./../../locales/tshared.js";
var locale = null;
locale = JSON.parse(loc) ;
Adapt path and names as needed, use locale at will.