Perpendicular

Perpendicular

perpendicular - two lines which intersect to form a right angle

2 Lines Intersection

Free 2 Lines Intersection Calculator - Enter any 2 line equations, and the calculator will determine the following:
* Are the lines parallel?
* Are the lines perpendicular
* Do the lines intersect at some point, and if so, which point?
* Is the system of equations dependent, independent, or inconsistent


Choose the equation of a line in standard form that satisfies the given conditions. perpendicular to

Choose the equation of a line in standard form that satisfies the given conditions. perpendicular to 4x + y = 8 through (4, 3). Step 1: Find the slope of the line 4x + y = 8. In y = mx + b form, we have y = -4x + 8. The slope is -4. To be perpendicular to a line, the slope must be a negative reciprocal of the line it intersects with. Reciprocal of -4 = -1/4 Negative of this = -1(-1/4) = 1/4 Using our [URL=' calculator[/URL], we get [B]y = 1/4x + 2[/B]


Explain the steps you would take to find an equation for the line perpendicular to 4x - 5y = 20 and

Explain the steps you would take to find an equation for the line perpendicular to 4x - 5y = 20 and sharing the same y-intercept Get this in slope-intercept form by adding 5y to each side: 4x - 5y + 5y = 5y + 20 Cancel the 5y's on the left side and we get: 5y + 20 = 4x Subtract 20 from each side 5y + 20 - 20 = 4x - 20 Cancel the 20's on the left side and we get: 5y = 4x - 20 Divide each side by 5: 5y/5 = 4x/5 - 4 y = 4x/5 - 4 So we have a slope of 4/5 to find our y-intercept, we set x = 0: y = 4(0)/5 - 4 y = 0 - 4 y = -4 If we want a line perpendicular to the line above, our slope will be the negative reciprocal: The reciprocal of 4/5 is found by flipping the fraction making the numerator the denominator and the denominator the numerator: m = 5/4 Next, we multiply this by -1: -5/4 So our slope-intercept of the perpendicular line with the same y-intercept is: [B]y = -5x/4 - 4[/B]


If MN is perpendicular to PQ and the slope of PQ is -4 what is the slope for MN

If MN is perpendicular to PQ and the slope of PQ is -4 what is the slope for MN the slope of a line perpendicular to another line is the negative reciprocal. Therefore: Slope of MN = -1/Slope of PQ Slope of MN = -1/-4 Slope of MN = [B]1/4[/B]


If the slope is 6 what would the slope of a line parallel to it be?

If the slope is 6 what would the slope of a line parallel to it be? Our rule for the relation of second lines to first lines with regards to slope is this: [LIST] [*]Parallel lines have the [U]same[/U] slope [*]Perpendicular lines have the [U]negative reciprocal[/U] slope [/LIST] So the slope of the line parallel would also be [B]6[/B]


Line m passes through points (3, 16) and (8, 10). Line n is perpendicular to m. What is the slope of

Line m passes through points (3, 16) and (8, 10). Line n is perpendicular to m. What is the slope of line n? First, find the slope of the line m passing through points (3, 16) and (8, 10). [URL=' the points into our search engine[/URL], we get a slope of: m = -6/5 If line n is perpendicular to m, then the slope of n is denote as: n = -1/m n = -1/-6/5 n = -1*-5/6 n = [B]5/6[/B]


Line m passes through points (7, 5) and (9, 10). Line n passes through points (3, 1) and (7, 10). Ar

Line m passes through points (7, 5) and (9, 10). Line n passes through points (3, 1) and (7, 10). Are line m and line n parallel or perpendicular [U]Slope of line m is:[/U] (y2 - y1)/(x2 - x1) (10 - 5)/(9 - 7) 5/2 [U]Slope of line n is:[/U] (y2 - y1)/(x2 - x1) (10 - 1)/(7 - 3) 9/4 Run 3 checks on the slopes: [LIST=1] [*]Lines that are parallel have equal slopes. Since 5/2 does not equal 9/4, these lines [B]are not parallel[/B] [*]Lines that are perpendicular have negative reciprocal slopes. Since 9/4 is not equal to -2/5 (the reciprocal of the slope of m), these lines [B]are not perpendicular[/B] [*][B]Therefore, since the lines are not parallel and not perpendicular[/B] [/LIST]


Plane and Parametric Equations in R3
Free Plane and Parametric Equations in R3 Calculator - Given a vector A and a point (x,y,z), this will calculate the following items:
1) Plane Equation passing through (x,y,z) perpendicular to A
2) Parametric Equations of the Line L passing through the point (x,y,z) parallel to A

The perpendicular height of a right-angled triangle is 70 mm longer than the base. Find the perimete

The perpendicular height of a right-angled triangle is 70 mm longer than the base. Find the perimeter of the triangle if its area is 3000. [LIST] [*]h = b + 70 [*]A = 1/2bh = 3000 [/LIST] Substitute the height equation into the area equation 1/2b(b + 70) = 3000 Multiply each side by 2 b^2 + 70b = 6000 Subtract 6000 from each side: b^2 + 70b - 6000 = 0 Using our [URL=' calculator[/URL], we get: b = 50 and b = -120 Since the base cannot be negative, we use b = 50. If b = 50, then h = 50 + 70 = 120 The perimeter is b + h + hypotenuse Using the [URL=' calculator[/URL], we get hypotenuse = 86.02 Adding up all 3 for the perimeter: 50 + 70 + 86.02 = [B]206.02[/B]


Vectors

Free Vectors Calculator - Given 2 vectors A and B, this calculates:
* Length (magnitude) of A = ||A||
* Length (magnitude) of B = ||B||
* Sum of A and B = A + B (addition)
* Difference of A and B = A - B (subtraction)
* Dot Product of vectors A and B = A x B
A ÷ B (division)
* Distance between A and B = AB
* Angle between A and B = θ
* Unit Vector U of A.
* Determines the relationship between A and B to see if they are orthogonal (perpendicular), same direction, or parallel (includes parallel planes).
* Cauchy-Schwarz Inequality
* The orthogonal projection of A on to B, projBA and and the vector component of A orthogonal to B → A - projBA
Also calculates the horizontal component and vertical component of a 2-D vector.


What is a Perpendicular Bisector

Free What is a Perpendicular Bisector Calculator - This lesson walks you through what a perpendicular bisector is and the various properties of the segment it bisects and the angles formed by the bisection


David Miller
Author

David Miller

David Miller brings 15 years of experience in global economics, personal finance strategy, and market dynamics. He specializes in turning complex economic trends into actionable insights for everyday readers.