With a steady state DC current flowing through the inductor and therefore zero induced voltage across it, the inductor acts as a short circuit equal to a piece of wire, or at the very least a very low value resistance.

How does inductor behave when a steady current flow through it?

When a steady state DC current will flow through the inductor, the inductor will acts as a short circuit equal to a piece of wire.

What is the voltage across an inductor at steady-state?

When a circuit is first energized, the current through the inductor will still be zero, which is characteristic of opens. Once at steady-state, the current has leveled out and therefore the voltage across the inductor will approach zero, which is characteristic of shorts.