When incident wavelength is lamda, stopping potential is 3V_0.
What is the relation between stopping potential and wavelength?
Given: Stopping potential = Vs = 2 V, wavelength of incident light = λ = 2000 Å = 2000 x 10-10 m, speed of light = c = 3 x 108 m/s, Planck's constant = h = 6.63 x 10-34 Js, Charge on electron = e = 1.6 x 10-19 C.
When light of wavelength lambda is incident on a metal surface the stopping potential?
When light of wavelength lambda is incident on a metal surface, stopping potential is found to be x. When light of wavelength nlambda is incident on the same metal surface, stopping potential is found to be (x)/(n+1) .
