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How do you write a while loop in Linux?
Syntax of while loop:
- n=1. while [ $n -le 5 ] do. echo “Running $n time” (( n++ )) done.
- n=1. while [ $n -le 10 ] do. if [ $n == 6 ] then. echo “terminated” break. fi. echo “Position: $n” (( n++ )) done.
- n=0. while [ $n -le 5 ] do. (( n++ )) if [ $n == 3 ] then. continue. fi. echo “Position: $n” done.
How do you use a while loop in Unix?
Syntax. Here the Shell command is evaluated. If the resulting value is true, given statement(s) are executed. If command is false then no statement will be executed and the program will jump to the next line after the done statement.
