Those are the “eigenvectors”.
Multiply an eigenvector by A, and the vector Ax is a number λ times the original x. The basic equation is Ax = λx. The number λ is an eigenvalue of A. ... All eigenvalues “lambda” are λ = 1.
Is λ an eigenvalue of a − 1b?
Therefore λ−1 is an eigenvalue for A−1 , since x = 0. 26.
Is λ 3 an eigenvalue of A?
E. Yes, lambda is an eigenvalue of A because lambda Ax = 0 only has the trivial solution.
