Therefore, the smallest number which when diminished by 7, is divisible 12, 16, 18, 21 and 28 is 1015.

What is the least number which when decreased by 7 is divisible by each one of 15 21 30?

Step-by-step explanation:

So the required number is 1015.

What is the least number which when increased by 7 is divisible by each one of 24 32 36 54?

Explanation: Required number = (L.C.M. of 24, 32, 36, 54) - 5 = 864 - 5 = 859. The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is : A.