Salkowski Reagent (prepared for the class): In the fume hood, mix 2 ml 0.5M FeCl₃ and 49 ml water and 49 ml 70% perchloric acid (Oxidizer! Corrosive!). 0.5M ferric chloride solution: the formula/molecular weight is 270.3 so you would need 270.3 g for a liter of 1 M solution. For 10 ml, you would need 2.7g for 1 M.

How do you make salkowski reagent?

Salkowski reagent consisted of a mixture of 15 ml 0.5 M FeCl3, 500 ml distilled water, and 300 ml of concentrated H,S04 sp.

What is Salkowski reagent?

Salkowski reagent is a mixture of 0.5 M ferric chloride (FeCl₃ ) and 35% perchloric acid (HClO₄) which upon reaction with IAA yields pink color, due to IAA complex formation with and reduction of Fe³⁺ ( Kamnev et al., 2001 ).